You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

1st Equation of Motion

A 100 N for...

Question

A $100 N$ force acts horizontal on a block of mass $10 k g$ placed on a horizontal rough table of coefficient of friction $μ = 0.5$ . If $g$ the placed is $10 m s^{- 2}$ , the acceleration of the block is:

z e r o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 m s^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 m s^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5.2 m s^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5 m s^{- 2}$
Force of friction= $μ m g$
= $0.5 \times 10 \times 10$
= $50 N$
Net force = $m a s s \times a c c e l e r a t i o n$
$100 N - 50 N = 10 a$
$a = 5 m / s^{2}$

Suggest Corrections

Similar questions

Q. A block of mass

10 kg

is placed on rough horizontal surface whose coefficient of friction is

0.5

. If a horizontal force of

100 N

is applied on it, then acceleration of block will be [Take

g = 10 {ms}^{- 2}

]

Q. A block of mass

10 k g

is placed on a rough horizontal surface whose coefficient of friction is

0.5

. If a horizontal force of magnitude

100 N

is applied on the block, then acceleration of the block will be

[Take g = 10 m s^{- 2}]

Q. A block of mass

10 k g

is pushed by a force

F

on a horizontal rough surface moves with an acceleration

5 m s^{- 2}

. When the horizontal force is doubled, it gets an acceleration of

18 m s^{- 2}

. Then the coefficient of friction is (assume

g = 10 m s^{- 2}

)

Q. A

3 k g

block is placed over a

10 k g

block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is

0.2

. If a horizontal force of

20 N

is applied to

3 k g

block, accelerations of the two bodies in

{m s}^{- 2}

are:
(

g = 10 {m s}^{- 2}

)

Q.
Block A mass 2 kg is placed over a block

B

mass 8 kg. The
combination is placed on a rough horizontal surface. If

g = 10 m s^{- 2}

,
coefficient offiiction between

B

and floor

= 0.5

, coefficient offfiction
betweenA and

B = 0.4

and a horizontal force on 10

N

is placed of8 kg
block, then the force friction between A and

B

is:

Join BYJU'S Learning Program

A 100 N force acts horizontal on a block of mass 10 kg placed on a horizontal rough table of coefficient of friction μ=0.5. If g the placed is 10 ms−2 , the acceleration of the block is:

The correct option is B 5 ms−2Force of friction=μmg =0.5×10×10 =50NNet force =mass×acceleration 100N−50N=10aa=5m/s2

A $100 N$ force acts horizontal on a block of mass $10 k g$ placed on a horizontal rough table of coefficient of friction $μ = 0.5$ . If $g$ the placed is $10 m s^{- 2}$ , the acceleration of the block is:

The correct option is B $5 m s^{- 2}$
Force of friction= $μ m g$
= $0.5 \times 10 \times 10$
= $50 N$
Net force = $m a s s \times a c c e l e r a t i o n$
$100 N - 50 N = 10 a$
$a = 5 m / s^{2}$