Question

A 100 N force acts horizontally on a block of mass 10 kg placed on a horizontal rought table of coefficient of friction $\mu =\mathrm{0.5.}$ If g at the place is $10m{s}^{-2},$ the acceleration of the block is

• A. Zero
• B. $10m/s^2$
• C. $5m/s^2$
• D. $5.2m/s^2$

Answer 1

The correct option is C $5m/s^2$

$F_{net}=ma$
$F-\mu mg=ma$
$a=\frac{F-\mu mg}{m}=\frac{100-0.5\times 10\times 10}{10}=5m/s^2$.