Question

A $100\Omega$ resistance and a capacitor of $100\Omega$ reactance are connected in series across a $220V$ source. When the capacitor is $50\%$ charged, the peak value of the displacement current is

• A. $4.4A$
• B. $11\sqrt{2}A$
• C. $2.2A$
• D. $11A$

Answer 1

The correct option is C $2.2A$

As we know the maximum value of the displacement current is equal to the maximum value of the capacitor current so,
${\left(i_d\right)}_{max}={\left(i_c\right)}_{max}=i_0=\frac{{\epsilon }_0}{Z}=\frac{220\sqrt{2}}{\sqrt{{100}^2+{100}^2}}=2.2A$