Question

A 100 pF capacitor is connected to a 50 Hz voltage supply that produces an rms voltage of 110 V. What is the maximum charge that appears on either of the capacitor plates ?

• A. $1.5\times {10}^{-5}$ C
• B. $1.8\times {10}^{-5}$ C
• C. $1.2\times {10}^{-5}$ C
• D. $2.4\times {10}^{-5}$ C

Answer 1

The correct option is A $1.5\times {10}^{-5}$ C

$Q_{max}=C{V}_{max}=C\left(V_{rms}\right)\sqrt{2}$
$=100\times {10}^{-9}\times 110\times \sqrt{2}$
$=1.1\times \sqrt{2}\times {10}^{-5}=1.5\times {10}^{-5}$ C