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House Wiring

A100 W bulb B...

Question

A 100 W bulb B₁two 60 W bulb B₂ and B₃ are connected to a 250 V source as shown in the figure. Now W₁, W₂ and W₃ are the output powers of the bulbs B₁, B₂ and B₃ respectively. Then

A

W₁> W₂ = W₃

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B

W₁> W₂> W₃

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C

W₁< W₂ = W₃

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D

W₁< W₂< W₃

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Solution

The correct option is D
W₁< W₂< W₃

Voltage across B₃ is greatest; hence B₃ will show maximum brightness. In series combination of bulbs, the bulb of lesser wattage will glow more bright.
Hence W₂> W₁.So, W₁< W₂< W₃.

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