A $100 w a t t$ bulb is connected to $200 v o l t s$ main. The resistance of the filament of the bulb is

400 o h m

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100 o h m

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200 o h m

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50 o h m

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Solution

The correct option is A $400 o h m$
Power in resistor is given by
$P = \frac{V^{2}}{R}$
$P = 100 W a t t$ $V = 200 V o l t s$
$∴ R = \frac{V^{2}}{P} = \frac{200 \times 200}{100} = 400 o h m$ .

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A 100watt bulb is connected to 200volts main. The resistance of the filament of the bulb is

The correct option is A 400ohmPower in resistor is given byP=V2RP=100Watt V=200Volts∴R=V2P=200×200100=400ohm.

A $100 w a t t$ bulb is connected to $200 v o l t s$ main. The resistance of the filament of the bulb is

The correct option is A $400 o h m$
Power in resistor is given by
$P = \frac{V^{2}}{R}$
$P = 100 W a t t$ $V = 200 V o l t s$
$∴ R = \frac{V^{2}}{P} = \frac{200 \times 200}{100} = 400 o h m$ .