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Standard X

Physics

Velocity Ratio

A 1000 kg aut...

Question

A 1000 kg automobile is moving along a straight highway at $10 m s^{1}$ . Another car with mass 2000kg and speed $10 m s^{1}$ is 30m ahead of the first. The position of the center of mass of the system from the first is:

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10m

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20m

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30m

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Solution

The correct option is C 20m
$X_{c o m} = \frac{2200 \times 30}{2000 + 1000} = \frac{2000 \times 30}{2000} = 20 m$ .

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A 1000 kg automobile is moving along a straight highway at 10ms1. Another car with mass 2000kg and speed 10ms1 is 30m ahead of the first. The position of the center of mass of the system from the first is:

The correct option is C 20mXcom=2200×302000+1000=2000×302000=20 m.

A 1000 kg automobile is moving along a straight highway at $10 m s^{1}$ . Another car with mass 2000kg and speed $10 m s^{1}$ is 30m ahead of the first. The position of the center of mass of the system from the first is:

The correct option is C 20m
$X_{c o m} = \frac{2200 \times 30}{2000 + 1000} = \frac{2000 \times 30}{2000} = 20 m$ .