wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 1,000 kg car moving at a speed of 20 m s–1 is brought to rest in a distance of 50 m. Calculate the net force acting on the car.


A

(-) 4000 N, More

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

3000 N, Less

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

2000 N, more

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

1000 N, more

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

(-) 4000 N, More


For calculating force, we need to calculate deceleration first. Now,
v2u2=2aS
Here, u=20m/s, S=50m and v=0. Therefore,
0202=2×a×50
a=4 m/s2

From Newton's second law,
F=ma
F=1000×(4)=4000 Newtons
Hence, the net force is -4000 Newtons. The negative sign indicates that the force is acting opposite to the direction of initial velocity and causes deceleration. This net force is actually the frictional force acting between the ground and the tyre of the car.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon