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Question

A 1,000 kg car moving at a speed of 20 ms−1 is brought to rest in a distance of 50 m. Calculate the net force acting on the car. Take the direction of movement of car as the positive direction.

A
4000 N
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B
4000 N
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C
2000 N
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D
2000 N
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Solution

The correct option is A 4000 N
Given:
Mass of car m=1000 kg
Initial velocity u= 20ms1
Distance travelled s=50 m
Car is brought to rest, so final velocity v=0 ms1

Let a be the acceleration of the car before coming to rest.
Let F be the force acting on the car.

For calculating force, we need to calculate acceleration first.
Using second equation of motion:
v2u2=2as
02202=2×a×50
a=4 m/s2

From Newton's second law of motion,
F=ma
F=1000×(4)
F=4000 N

Note- The negative sign indicates that the force is acting opposite to the direction of initial velocity and causes deceleration.

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