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Question

A 1,000 kg car moving at a speed of 20ms1​ is brought to rest at a distance of 50 m, calculate the unbalanced force acting on the car and give a reason why the actual force applied by the brakes may be slightly less than that calculated?


A

(-) 4000 N, More

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B

3000 N, Less

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C

2000 N, More

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D

1000 N, More

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Solution

The correct option is A

(-) 4000 N, More


Step 1: Here u = 20ms1​; v = 0; s = 50 m; a = ?

Using v2u2=2as, we have

a=v2u22s = 4ms2

Step2: F = ma = 1,000×(-4) = -4,000 N

Due to force of friction, the actual force applied by brakes may be slightly less than the calculated one.


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