A 1,000 kg vehicle moving with a speed of $20 m s^{- 1}$ is brought to rest in a distance of 50 m. Find the acceleration.

- 4 m s^{- 2}

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4 m s^{- 2}

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- 8 m s^{- 2}

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8 m s^{- 2}

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Solution

The correct option is A $- 4 m s^{- 2}$
$v^{2} - u^{2} = 2 a s$
$a = \frac{v^{2} - u 2}{2 s} = \frac{0 - (20)^{2}}{2 (50)} = - 4 m s^{- 2}$

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