Question

A $1000\text{N}$ thrust acting on a surface can exert a pressure of a million pascals. What will be the area (in ${\text{cm}}^2$) of the surface bearing the pressure?

Answer 1

Given:
Thrust, $\text{F}=1000\text{N}$
Pressure generated, $\text{P}={10}^6\text{Pa}=10,00,000\text{Pa}$
Let the area of the surface be $\text{A}$.
Pressure acting on a surface is given by $\text{P}=\frac{\text{F}}{\text{A}}$
$⟹\text{A}=\frac{\text{F}}{\text{P}}=\frac{1000\text{N}}{10,00,000\text{Pa}}$

$⟹\text{A}=\frac{1}{1000}{\text{m}}^2$

$[1{\text{m}}^2={10}^4{\text{cm}}^2]$

$⟹\text{A}=\frac{1}{1000}\times {10}^4{\text{cm}}^2=10{\text{cm}}^2$

Therefore, the area bearing the pressure is $10\text{sq.cm.}$