A $100 V$ carrier wave is made to vary berween $160 V$ and $40 V$ by a modulating signal. What is the modulation index?

0.6

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0.5

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0.3

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0.4

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Solution

The correct option is A 0.6
Given:
Modulated voltage $A_{c} = 100$
Range of modulated voltage $A_{c} + A_{m} = 160$
$A_{C} - A_{m} = 40$
$A_{c} = 100$ and $A_{m} = 40$
Hence, modulation index
$μ = \frac{A_{m}}{A_{c}} = 0.6$

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