A 10g bullet is fired at a plank of wood with a speed of 200ms−1. After passing through the plank, which is 1m thick, the speed of the bullet reduces to 100ms−1. Find the average resistance offered by the plank.
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Solution
Using v2=u2−2as and putting v=100m/s, u=200m/s and s=1m
we get retardation a=1.5×104m/s2
so average resitance offered F=ma=(10/1000)1.5×104=150Kgm/s2=150Newton