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Second Law of Motion

A 10 g bullet...

Question

A 10g bullet is moving at 200m/s stops after penetrating 5cm of wooden plank. What will be the average force exerted on the bullet?

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Solution

Given :
mass=10g=10/1000=0.01kg
Initial speed=u=200m/s
final velocity= 0 m/s
S=5cm=5/100=0.05m

From third equation of motion : V²-u²=2as

0²-(200)²=2a0.05

-40000=a/10

a=-400000m/s²

From Newton's Second law:
F=ma
=0.01(-400000)
=-4000N

∴ A force of 4000N acts in opposite direction

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