A $10 g$ bullet moving at $200 m / s$ stops after penetrating $5 c m$ of wooden plank. The average force exerted on the bullet will be

2000 N

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- 2000 N

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4000 N

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- 4000 N

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Solution

The correct option is C $4000 N$
Using $v^{2} = u^{2} - 2 a s$ and putting $f i n a l$ velocity $v = 0$ and $s = 0.05 m$
we get average acceleration $a = u^{2} / 2 s = 40000 / (2 \times 0.05) = 400000 m / s^{2}$
Average force $F = m a s s \times a c c e l e r a t i o n = .001 \times 400000 = 4000 N$ Option C is correct.

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