Question

A 10kg mass moves along X-axis. Its acceleration as a functions of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from x=0 to x=8cm?

• A. $8\times {10}^{-2}J$
• B. $16\times {10}^{-2}J$
• C. $4\times {10}^{-4}J$
• D. $1.6\times {10}^{-3}J$

Answer 1

The correct option is A $8\times {10}^{-2}J$

$W={\int }_{x_i}^{x_f}f\left(u\right)du$,

$W={\int }_{x_i}^{x_f}m.adu$

$W=2.5{\int }_0^{8}xdu$ $y=m\times tb$

$=\frac{2.5}{2}{x}^2{]}_0^8$ $a=mx$

$=80J$ $a=2.5x$