Question

A $10L$ container is filled with a gas to a pressure of $2atm$ at $0^{0}C.$ At what temperature will the pressure inside the container be $2.50atm?$

• A. ${68}^{0}C$
• B. ${50}^{0}C$
• C. ${40}^{0}C$
• D. ${45}^{0}C$

Answer 1

The correct option is A ${68}^{0}C$

As the volume of the container remains constant, applying pressure-temperature law,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

We get,

$\frac{2atm}{273K}=\frac{2.50atm}{T_2}$

or

$T_2=314K=341-273={68}^{0}C$