Question

A $110V.60W$ lamp is run from a $220V$ AC mains using a capacitor in series with the lamp, instead of a resistor then the voltage across the capacitor is about:

• A. $110V$
• B. $190V$
• C. $220V$
• D. $311V$

Answer 1

Answer: (B)

$190V$

$V_c=\sqrt{V^2-V_R^2}$

$=\sqrt{{220}^2-{110}^2}$

$=190V$