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Question
A 112-bus power system has 91 PQ buses and 20 PV buses. In the general case, to obtain the load flow solution using Newton-Raphson method in polar co-ordinates, the minimum number of simultaneous equations to be solved are
A 112-bus power system has 91 PQ buses and 20 PV buses. In the general case, to obtain the load flow solution using Newton-Raphson method in polar co-ordinates, the minimum number of simultaneous equations to be solved are
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Solution
The correct option is C 202
From given:
n= total number of buses = 112
m= PV buses = 20
Maximum number of equations
=2n−m−2
=2(112)−20−2
=202
From given:
n= total number of buses = 112
m= PV buses = 20
Maximum number of equations
=2n−m−2
=2(112)−20−2
=202
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