Question

A 12 mm thick plate is connected to two 8 mm thick plates, on either side through a 16 mm diameter power driven field rivet as shown in the figure below. Assuming permissible shear stress as 90 MPa and permissible bearing stress as 270 MPa in the rivet, the rivet value of the joint is ________.

• A. 21.65 kN
• B. 36.19 kN
• C. 43.29 kN
• D. 56.70 kN

Answer 1

The correct option is C 43.29 kN

Permissible shear stress,
${\tau }_{per}=90MPa$

Permissible bearing stress,
${\sigma }_{br}=270MPa$

Nominal diameter of rivet,
d = 16 mm

Gross diameter
d' = d + 1.5
= 17.5 mm

Rivet is in double shear
Rivet value = Min {strength of rivet in shearing, strength of rivet in bearing}

$=Min\{2\times \frac{\pi d^{\prime 2}}{4}\times {\tau }_{per},(d^{\prime }\times t\left){\sigma }_{br}\right\}$

$=Min\{2\times \frac{\pi \times {17.5}^2}{4}\times 90N,17.5\times 12\times 270N\}$

= Min {43.29 kN,.56.7 kN}
= 43.29 kN