A $120$ m long ladder reached a window $72$ m from the ground on placing it against a wall. Find the distance of the foot of the ladder from the wall.

85

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96

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Solution

The correct option is C $96$ m
$x^{2} + (72)^{2} = (120)^{2}$
So, $⟹ x = \sqrt{(120)^{2} + (72)^{2}}$
$⟹ x = 96 m$

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A 120m long ladder reached a window 72m from the ground on placing it against a wall. Find the distance of the foot of the ladder from the wall.

The correct option is C 96mx2+(72)2=(120)2So, ⟹x=√(120)2+(72)2⟹x=96m

A $120$ m long ladder reached a window $72$ m from the ground on placing it against a wall. Find the distance of the foot of the ladder from the wall.

The correct option is C $96$ m
$x^{2} + (72)^{2} = (120)^{2}$
So, $⟹ x = \sqrt{(120)^{2} + (72)^{2}}$
$⟹ x = 96 m$