A $120 m$ long train is going from East to West with velocity $10 m s^{- 1}$ A bird, flying due East with velocity $5 m s^{- 1}$ , crosses the train. Calculate the time taken by the bird to cross the train.

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Solution

Given,
Displacement = length of train
Relative velocity of bird with respect to train, $V_{B A} = 5 - (- 10) = 15 m s^{- 1}$
Time, $t = \frac{d i s p l a c e m e n t}{v e l o c i t y} = \frac{120}{15} = 8 sec$
Hence, time taken by bird to cross the train is $8 s e c$

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A 120m long train is going from East to West with velocity 10m s−1 A bird, flying due East with velocity 5m s−1, crosses the train. Calculate the time taken by the bird to cross the train.

Given,Displacement = length of trainRelative velocity of bird with respect to train, VBA=5−(−10)=15ms−1Time, t=displacementvelocity=12015=8sec Hence, time taken by bird to cross the train is 8sec

A $120 m$ long train is going from East to West with velocity $10 m s^{- 1}$ A bird, flying due East with velocity $5 m s^{- 1}$ , crosses the train. Calculate the time taken by the bird to cross the train.

Given,
Displacement = length of train
Relative velocity of bird with respect to train, $V_{B A} = 5 - (- 10) = 15 m s^{- 1}$
Time, $t = \frac{d i s p l a c e m e n t}{v e l o c i t y} = \frac{120}{15} = 8 sec$
Hence, time taken by bird to cross the train is $8 s e c$