$A = {1, 2, 4}, B = {2, 4, 5}, C = {2, 5},$ then $(A - B) \cup (B - C)$ is

{1, 2, 5}

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{1, 4}

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{1, 3}

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None of these.

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Solution

The correct option is B ${1, 4}$
$A - B = {1}, B - C = {4}$
$⟹ (A - B) U (B - C) = {1, 4}$

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If A = {1, 2, 4}, B = {2, 4, 5} C = {2, 5}, then $(A - B) \times (B - C)$ is

A = {1, 2, 4}, B = {2, 4, 5}, C = {2, 5}

(A - B) \times (B - C)

A = {1, 2, 4}, B = {2, 4, 5}, C = {2, 5}

(A - C) \times (B - C)

A = {1, 2, 4}, B = {2, 4, 5}

C = {2, 5}

(A - B) \times (B - C) =

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