Question

A 12pF capacitor is connected to a 50 V battery . How much of electrostatic energy is stored in the capacitor?

Answer 1

Energy stored in capacitor: $E=\frac{1}{2}C{V}^2$

$=\frac{1}{2}\times (12\times {10}^{-12})(50{)}^2$

$=6\times 2500\times {10}^{-12}$

$=15\times {10}^{-9}J$