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Standard XII

Physics

Root Mean Square Speed

A 15 g mass o...

Question

A 15 g mass of nitrogen gas is enclosed in a vessel at a temperature $27^{o} C$ . Amount of heat transferred to the gas, so that rms velocity of molecules is doubled, is about :

10 kJ

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0.9 kJ

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6 kJ

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14 kJ

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Solution

The correct option is A 10 kJ
$Q = n C_{v} Δ T$ as gas in closed vessel
$Q = \frac{15}{28} \times \frac{5 \times R}{2} \times (4 T - T)$
$Q = 10000 J = 10 k J$

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Similar questions

Q. If

15 g

mass of nitrogen gas is enclosed in a vessel at a temperature

27^{\circ} C

. Amount of heat transfered to the gas, so that rms velocity of molecules is doubled is about
[Take

R = 8.3 J/K mole

]

Q. About

0.014 k g

of nitrogen is enclosed in a vessel temperature of

27^{\circ} C

. How much heat has to be transferred to the gas to double the rms speed of its molecules?

(R = 2 c a l / m o l K)

Q. 0.014 kg of nitrogen is enclosed in a vessel at

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. The heat given to gas in order to double its rms speed is

$0.014 k g$ of nitrogen is enclosed in a vessel at a temperature of $27^{\circ} C$ . The amount of heat energy to be supplied to the gas to double the rms speed of its molecules is approximately equal to

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. How much heat has to be transferred to the gas to double the most probable speed of its molecules? (R

= 2

cal/mol.k)

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A 15 g mass of nitrogen gas is enclosed in a vessel at a temperature 27oC. Amount of heat transferred to the gas, so that rms velocity of molecules is doubled, is about :

The correct option is A 10 kJQ=nCvΔT as gas in closed vesselQ=1528×5×R2×(4T−T)Q=10000J=10kJ

A 15 g mass of nitrogen gas is enclosed in a vessel at a temperature $27^{o} C$ . Amount of heat transferred to the gas, so that rms velocity of molecules is doubled, is about :

The correct option is A 10 kJ
$Q = n C_{v} Δ T$ as gas in closed vessel
$Q = \frac{15}{28} \times \frac{5 \times R}{2} \times (4 T - T)$
$Q = 10000 J = 10 k J$