Question

A $15$ liter of a mixture contains $20\%$ alcohol and rest water. if $3$ liter of water is added in it, find the $\%$ of alcohol in the new mixture.

• A. $16.66\%$
• B. $26.66\%$
• C. $15\%$
• D. $20\%$

Answer 1

Answer: (A)

$16.66\%$

Mixture $=15$ liter.

It contain $20\%$ alcohol.

Alcohol $=20\%$ of $15=$ $\frac{20}{100}\times 15=3$ liter.

Water $=$ $12$ liter

Now, $3$ liter water is added,

Water become $=$ $12+3=15$ liter.

Total mixture $=$ $15+3=18$ liter.

Now, $\%$ of Alcohol into new mixture $=$ $\frac{3\times 100}{188}=16.66\%$