A 15 m long ladder reached a window 12 m high from the ground. On placing it against a wall at a distance $x$ m. Find $x$ .

Open in App

Solution

By Pythagoras Theorem,
$15^{2} = 12^{2} + (d i s t a n c e)^{2}$
$\Rightarrow$ Distance, $x = \sqrt{15^{2} - 12^{2}} = 9 m$

Suggest Corrections

Similar questions

A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.

Question 3
A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.

Q. A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance 'a'. Find the distance of the foot of the ladder from the wall.

Q. A

15

m long ladder reaches a window

12

m high from the ground on placing it against a well. How far is the ladder from the well?

Join BYJU'S Learning Program

A 15 m long ladder reached a window 12 m high from the ground. On placing it against a wall at a distance x m. Find x.

By Pythagoras Theorem, 152=122+(distance)2⇒ Distance, x=√152−122=9m

A 15 m long ladder reached a window 12 m high from the ground. On placing it against a wall at a distance $x$ m. Find $x$ .

By Pythagoras Theorem,
$15^{2} = 12^{2} + (d i s t a n c e)^{2}$
$\Rightarrow$ Distance, $x = \sqrt{15^{2} - 12^{2}} = 9 m$