A 15g bullet is fired horizontally at a speed of 350m/s into 1.2kg block that hangs by a vertical string as shown below. The bullet remains embedded in the block. Find the speed of the bullet and the block.
A
10m/s
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B
22.5m/s
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C
350m/s
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D
4.32m/s
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Solution
The correct option is D4.32m/s
Let V1= speed of bullet =350m/s V2= initial speed of block =0 V= final speed of block & bullet
(final speed will be same for the block & bullet because bullet is embedded in the block)
By conservation of momentum, Pi=Pf m1v1+m2v2=(m1+m2)V ⇒(0.015)×350+1.2×0=(0.015+1.2)×V ⇒V=4.32m/s