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Question

A 150 m long train accelerates uniformly from rest. If the front of the train passes a railway worker 50 m away from the station at a speed of 25 m/s, what will be the speed of the back part of the train as it passes the worker?

A
30 m/s
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B
40 m/s
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C
50 m/s
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D
60 m/s
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Solution

The correct option is C 50 m/s
Applying 3rd equation of motion
v2=u2+2as
25×25=0+2×a×50
a=254 m/s2
Now for speed of the back part of the train as it passes the worker
We have v2=v2+2al
where l is the length of the train or distance covered by the back part to pass the worker
v2=252+2×254×150
v2=625+(25×75)=2500
v=50 m/s

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