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Question

A 1500 kVA, 11 kV, 3ϕ star connected alternator has Ra and Xs of 1.2 Ω and 24 Ω respectively.
The value of generated voltage (line) at a load of 1200 kW, unity pf is

A
6601.79 V
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B
11434.64 V
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C
3681.14 V
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D
5493.16 V
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Solution

The correct option is B 11434.64 V
Ia=1200×1033×11×103=62.98A

Vph=110003=6350.85V

Ef=(Vcosϕ+IaRa)2+(Vsinϕ+IaXa)2

=(6350.85+62.98×1.2)2+(62.98×24)2=6601.79V

E(line)=6601.79×3=11434.64 V

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