Question

A 16kg block moving on a frictionless horizontal surface with a velocity of 4m/s compresses an ideal spring and comes at rest. If the force constant of spring be 100N/m, then how much is the spring compressed?

Answer 1

1/2 kx² = 1/2 mv²

1/2$\times$100$\times$x² = 1/2$\times$16$\times$(4)²

50$\times$x² = 256/2

x² = 128/50

x² = 2.56

x = 1.6

so, the spring is compressed 1.6 m .