Question

A $2.0cm$ long object is placed perpendicular to the principal axis of a concave mirror. The distance of the object from the mirror is $30cm$, and its image is formed $60cm$ from the mirror, on the same side of the mirror as the object. Find the height of the image formed :

• A. $3cm$
• B. $4cm$
• C. $5cm$
• D. $8cm$

Answer 1

The correct option is B $4cm$

Distance of object from the mirror, $u=-30$

Distance of image from the mirror, $v=-60$ , image is real.

Now we know magnification ratio $m=-\frac{v}{u}$

$m=-\frac{-60}{-30}$

$m=-2$

Height of object $h=2cm$

Image height $h_1=m\times h=-2\times 2=-4cm$

Height of image is 4 cm and its inverted .