A $2.00$ mole sample of an ideal gas is placed into a rigid $2.00 L$ vessel at $1.00 a t m$ .
What will the temperature of the gas be when the volume of the gas is reduced to $0 L$ ?

273^{\circ} C

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- 273^{\circ} C

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100^{\circ} C

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0^{\circ} C

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Solution

The correct option is B $- 273^{\circ} C$
$n = 2 V_{1} = 2 l P_{1} = 1 a t m \frac{T_{2}}{T_{1}} = \frac{P_{2} V_{2}}{P_{1} V_{1}} a s V_{2} = 0 l T_{2} = 0 K T_{1} = - 273 ℃$
Ans $= - 273 ℃$

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