a2−b2 is equal to(a) (a−b)2(b) (a−b)(a−b)(c) (a−b)(a+b)(d) (a+b)(a+b)
Lets evaluate a2−b2,
a2−b2
=a2−ab+ab−b2
=a(a−b)+b(a−b)
=(a−b)(a+b)
Therefore, a2−b2=(a−b)(a+b)
Hence, Option (c) is correct.