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Types of Brackets

a2-b2+z2+8 x-...

Question

$a^{2} - b^{2} + z^{2} + 8 x - 4 y$ = $a^{2} - (x)$ . Then $x$ equals

$b^{2} + z^{2} - 8 x - 4 y$

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$b^{2} + z^{2} - 8 x + 4 y$

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$b^{2} - z^{2} - 8 x + 4 y$

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$- b^{2} + z^{2} + 8 x - 4 y$

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Solution

The correct option is C
$b^{2} - z^{2} - 8 x + 4 y$

$a^{2} - b^{2} + z^{2} + 8 x - 4 y$

= $a^{2} - (b^{2} - z^{2} - 8 x + 4 y)$

$∴$ $x = b^{2} - z^{2} - 8 x + 4 y$

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