Let the digit at units place = y
and digit at tens place = x
Therefore, the original number becomes = 10x+y
According to first condition
10x+y = 4(x + y)
⇒10x+y=4x+4y
⇒10x-4x= 4y-y
⇒6x = 3y
or
y = 2x.....(i)
According to second condition :
10x+y = 2xy
⇒10x+2x = 2x(2x) [From(i)]
Now, from (i), we get,
y = 2(3)
y = 6
Thus, the number = 10x+y = 10(3) +6=30+6=36
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