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Standard X

Physics

Centripetal Force

A 2 kg ball o...

Question

A 2 kg ball on a string is rotated about a circle of radius 10 m. The maximum tension allowed in the string is 50 N. What is the maximum speed of the ball?

21.2 m/s

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15.8 m/s

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40.8 m/s

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11.11 m/s

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Solution

The correct option is B
15.8 m/s

Centripetal force is $T = F c = \frac{m v^{2}}{r}$

$\Rightarrow$ V= $\sqrt{\frac{T r}{m}}$

$= \sqrt{\frac{(10) (50)}{2}}$

= $15.8 m / s$

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A 2 kg ball on a string is rotated about a circle of radius 10 m. The maximum tension allowed in the string is 50 N. What is the maximum speed of the ball?

The correct option is B 15.8 m/s Centripetal force is T=Fc=mv2r ⇒ V= √Trm =√(10)(50)2 = 15.8m/s

The correct option is B
15.8 m/s

Centripetal force is $T = F c = \frac{m v^{2}}{r}$

$\Rightarrow$ V= $\sqrt{\frac{T r}{m}}$

$= \sqrt{\frac{(10) (50)}{2}}$

= $15.8 m / s$