A 2 kg block is dropped from a height of 0.4 m on a spring of force constant K=1960Nm−1. The maximum compression of the spring is?
Given:
Mass of the body is (m)=2Kg
spring's constant (K)=1960 N/m
Let comparetion of spring is x
mg(h+x)=12Kx²
2mgh+2mgx=Kx²
Kx²−2mgx−2mgh=0
⇒1960x²−2×2×9.8×x−2×2×9.8×0.4=0
⇒1960x²−39.2x−15.68=0
After solving this quadratic equations , we get x=0.1 m