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Question

A 2 kg block is placed over a 4 kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 020. Find the acceleration of the two blocks if a horizontal force of 12 N is applied to (a) the upper block, (b) the lower block. Take g=10m/s2.

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Solution

R12y=0

R1=2×10=20

2a+(0.2)(20)=12

a=4

4a1μR1=0

4a1=0.2×20

a1=1ms2

(ii)R1=2g=20

MaNR1=0

a=2

4a+0.2×2×1012

a=2



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