A $2 k g$ block is placed over a $4 k g$ block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is $0 - 20$ . Find the acceleration of the two blocks if a horizontal force of $12 N$ is applied to (a) the upper block, (b) the lower block. Take $g = 10 m / s^{2}$ .

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Solution

$R_{1} - 2 y = 0$

$R_{1} = 2 \times 10 = 20$

$2 a + (0.2) (20) = 12$

$a = 4$

$4 a_{1} - μ R_{1} = 0$

$4 a_{1} = 0.2 \times 20$

$a_{1} = 1 m s^{- 2}$

$(i i) R_{1} = 2 g = 20$

$M a - N R_{1} = 0$

$a = 2$

$4 a + 0.2 \times 2 \times 10 - 12$

$a = 2$

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A 2 kg block is placed over a 4 kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. Find the acceleration of the two blocks if a horizontal force of 12 N is applied to the upper block. Take g = 10 $m / s^{2}$ .

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