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Second Law of Motion

A 2 kg box ...

Question

A $2 k g$ box sits on a $3 k g$ box which sits on a $5 k g$ box. The $5 k g$ box rests on a table top. What is the normal force exerted by the $5 k g$ box on the $3 k g$ box?

A

19.6 N

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B

29.4 N

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C

49 N

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D

98 N

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Solution

The correct option is D $49 N$
The mass above the $5 k g$ box: $2 k g + 3 k g = 5 k g$
Force exerted by these masses will be equal to the normal force that $5 k g$ mass is applying.
Therefore,
$N = 5 \times g$
$⟹ N = 49 N$

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