Question

A $2kg$ mass kept on a horizontal table is acted upon by a force of $5N$ at an angle of ${60}^o$ from horizontal and moved through a distance of $3m$ on the table. the work done on the body is

• A. $5J$
• B. $7.5J$
• C. $10J$
• D. $15J$

Answer 1

The correct option is B

$7.5J$

Step 1: Given

Mass$=2kg$

Force$=5N$

Distance$=3m$

The angle between force and distance traveled is $\theta ={60}^{\circ }$

Step 2: Calculate the work done,

Work done on the body

$$\begin{gathered} \Rightarrow W=F\times S\times Cos\theta \\ \Rightarrow W=5\times 3\times Cos{60}^o \\ \Rightarrow W=15\times \frac{1}{2} \\ \Rightarrow W=7.5J \end{gathered}$$

Thus, we conclude that the work done on the body is $W=7.5J$.

Hence, option B is the correct answer.