A $2 k g$ object has an initial velocity of $u = 10 m s^{- 1}$ . The retardation due to friction is $2 m s^{- 2}$ . After what time does the object stop?

5 s

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2 s

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10 s

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8 s

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Solution

The correct option is A $5 s$
Given:
Initial velocity,
$u = 10 m s^{- 1}$
Final velocity,
$v = 0 m s^{- 1}$
Acceleration,
$a = - 2 m s^{- 2}$

Using first equation of motion:
$v = u + a t$
$\Rightarrow 0 = 10 - 2 t$
$\Rightarrow t = 5 s$

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A 2 kg object has an initial velocity of u=10 ms−1. The retardation due to friction is 2 ms−2. After what time does the object stop?

The correct option is A 5 sGiven: Initial velocity, u=10 ms−1Final velocity,v=0 ms−1Acceleration, a=−2 ms−2Using first equation of motion:v=u+at⇒0=10−2t⇒t=5 s

A $2 k g$ object has an initial velocity of $u = 10 m s^{- 1}$ . The retardation due to friction is $2 m s^{- 2}$ . After what time does the object stop?

The correct option is A $5 s$
Given:
Initial velocity,
$u = 10 m s^{- 1}$
Final velocity,
$v = 0 m s^{- 1}$
Acceleration,
$a = - 2 m s^{- 2}$

Using first equation of motion:
$v = u + a t$
$\Rightarrow 0 = 10 - 2 t$
$\Rightarrow t = 5 s$