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Question

A 2 kg stone is tied to a string of 2 m length & is whirled in a horizantal circle. If the breaking tension of the string is 400 N, the maximum velocity of the stone in ms−1 is :

A
40
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B
20
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C
10
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D
50
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Solution

The correct option is A 20
Mass of stone(m) = 2Kg,
radius(r) = length of rope =2m,
Maximum tension (Tmax) = 400N
The maximum tension acts as the centripetal force for the circular motion of the stone.
Let vmax be the maximum velocity.
Hence, F=Tmax=mv2maxr
v2max=Tmax×rm

vmax=Tmax×rm

vmax=400×22

vmax=20ms1

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