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Question

a2 (cos2 Bcos2 C)+b2 (cos2 Ccos2 A)+c2 (cos2 Acos2 B)=0

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Solution

a2 (cos2 Bcos2 C)+b2 (cos2 Ccos2 A)+c2 (cos2 Acos2 B)=0LHS=a2 (1sin2 B1+sin2 C)+b2 (1sin2 C1+sin2 A)+c2 (1sin2 A1+sin2 B)=a2 (sin2 Csin2 B)+b2 (sin2 Asin2 C)+c2 (sin2 Bsin2 A)=a2 (k2 c2k2 b2)+b2 (k2 a2k2 c2)+c2 (k2 b2k2 a2)=k2 (a2 c2a2 b2+b2 a2b2 c2+b2 c2a2 c2)=k2×0=0=RHS.


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