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Foundation Engineering

Modes of Shear Failure

A 2 m × 4 m r...

Question

A 2 m $\times$ 4 m rectangular footing has to carry a uniformly distributed load of 120 kPa. as per the 2 : 1 dispersion method of stress distribution, the increment in vertical stress (kPa) at a depth of 2 m below the footing is
40

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Solution

The correct option is A 40
Increment in the vertical stress

$= \frac{120 \times 2 \times 4}{(2 + h) (4 + h)}$

$= \frac{120 \times 2 \times 4}{(2 + 2) (4 + 2)}$

= 40 kPa

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