A 2μFcapacitor charged to 100 volt and then its plates are connected by a conducting wire. The heat produced is :
A
1J
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B
0.1J
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C
0.01J
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D
0.001J
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Solution
The correct option is C 0.01J
C=2μF,V=100V...(given)
Energy stored in the capacitor after charging the capacitor by 100V is given by,
12CV2=12×2×10−6×100×100 =10−2J=0.01J when a conducting wire is connected to the capacitor, capacitor gets discharging and current starts flowing through conducting wire in the circuit.
+v continues with −v and total charge on capacitor becomes 0. ∴ Whole energy is released as heat from the conducting wire. ∴ Heat produced in the conducting wire =0.01J