Given:
Length of the rod, l = 20 cm = 0.2 m
Velocity of the rod, v = 10 cm/s = 0.1 m/s
Magnetic field, B = 0.10 T
(a) The force on a charged particle moving with velocity v in a magnetic field is given by
F = qvB sin θ
Here,
θ = 90o
Now,
F = (1.6 × 10−19) × (1 × 10−1) × (1 × 10−1)
= 1.6 × 10−21 N
(b) The electrostatic force on the charged particle is qE.
Here,
qE = qvB
⇒ E = (1 × 10−1 ) × (1 × 10−1)
= 1 × 10−2 V/m
It is created because of the induced emf.
(c) Motional emf between the ends of the rod, e = Bvl
⇒ e = 0.1 × 0.1 × 0.2
= 2 × 10−3 V