A 20 gm particle is subjected to two simple harmonic motions x1=2sint; x2=4sin(10+π3), where x1 and x2 are in metre & t is sec.
A
The displacement of the particle at t = 0 will be 2√3m
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B
Maximum speed of the particle will be 20√7
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C
Magnitude of maximum acceleration of the particle will be 200√7m/s2
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D
Energy of the resultant motion will be 28 J
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Solution
The correct options are A The displacement of the particle at t = 0 will be 2√3m B Maximum speed of the particle will be 20√7 D Energy of the resultant motion will be 28 J